TCS 2013 placement new pattern questions 01

In a coding word 'INDIA'=90 AND 'FRANCE'=146. Then 'ENGLAND'=?

219 ans.......

1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4,…………………………………..
Then what is the 2320 position of the number in the sequence?
b) 2 b) 1c) 3 d) 4

 

answer is b)1
1,2,3,4(1-1time 2- 2times 3-3 4-4)=10 terms /completes cycle and starts from 1
1,2,3,4(1-2 2-4 3-6 4-8)= 20 terms /completes cycle and starts from 1
(1,2,3,4)each digit 3 time to its value =30 terms/completes cycle and starts from 1

10+20+30+40+50+.......=x
x is nearer value to 2320 solving n(n+1)/2
10.(21.22)/2= 2310
analysing it 2310 completes cycle and starts from 1 again
now it 22 times
(1-22 times 2-44 times ......)
2320 position will occupied by 1

 

drawer hold 4 red hat and 4 blue hat.what is probabilty of getting exactly 3 red hatexactly 3 blue hatwhen taking 4 hat randomly out of drawer when immediately returning every haTto drawer before taking out of nextoption(a)1/2(b)1/8)(c)1/4(c)3/8)

What is the value of

44444445*88888885*444444442*44444438/44444448^2

a)88888883 b)88888884 c)88888888 d)44444443

Asked In TCS Submited By-- Prabhu (4 Hour ago)

Puzzle Status: Unsolved Read Solution (3)

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Prabhu  (3 Hour ago)

What is the value of

44444445*88888885*44444442*44444438/44444448^2

a)88888883 b)88888884 c)88888888 d)44444443

take x=44444444
thn given question can be written as
(x+1)(2x-3)(x-2)+(x-6)/x^2

solving we get 2x-5

subt x=44444444 in 2x-5 we get ans as 88888883

From 5 men and 11 women in how many ways can a panel of 11 be formal such that the number of the men is not more than 3.
a) 1650
b) 2255
c) 5522
d) None of these.

if we consider 0-men and 11-women case also den d ans comes 2256 ie (d).....guys should we consider dat case or not??

for which of the following n is the number 2^74 + 2^2058 + 2^2n is a perfect square

We know that a^2 + 2ab + b^2 = (a+b)^2
Here, 2^74 + 2^2058 + 2^2n = (2^37)^2 + 2*2^37*2^2020 + (2^n)^2
If the number is a perfect square, then 2^n should equal 2^2020.
Hence, n=2020

4 persons have to cross the bridge. Their speeds are 1, 2, 5, 10 min respectively. Only two persons can cross at a time and as it is night they have to carry torch (i.e. one have to return with the torch). What is the minimum time required for all of them to reach the other side? When two persons cross they go by the speed of slowest one

there is bridge.one side of the bridge one family is standing to cross the bridge.that is mid night.they have only one light.there
is chance will go other side at tome two members.i more then two members are go at a time the bridge id break,and they have only 17 min to go the other end other wise the bridge will cross with in that time .boy take 1 min to cross bridge,baby take 2 min to cross bridge ,mother take 5 min to cross bridge and father take 10 min to cross
bridge.

Boy + baby cross in 2 mins,
Boy comes back in 1 min.
Father and mother cross in 10 mins.
Baby comes back in 2 mins
boy and baby cross in 2 mins.

Total 17 mins

In a certain quiz competition a candidate can win, if he answers all the 5 questions. If a candidate appears for the quiz and he is sure about the answers of first two answers, but 50% sure about third,75% sure about fourth and 25% sure about the fifth question's answers of the quiz.Then what is the probability that candidate appeared for quiz will win?

Probabilities for each answer would be as follows :
1*1*(1/2)*(3/4)*(1/4) = 3/32 = 0.0937

Since it is given in question that a candidate can win if he answers all questions.And not that he can win means he has already won.

find the remainder when 3^164 divided by 162

remainder is 1...

we can write 162 as 2*81=2*(3^4)
so (3^164)/(2*(3^4))=(3^160)/2
3 power any thing will result an odd integer... ( like 3,9,27,81...)
so 3^160 is an odd integer...
we all know any odd integer divided by 2 will result 1 as remainder...
so 1 is the remainder...

n! has 13 zeros than wat is the higest and lowest value of n??

Here we have to consider only the 5,10,15,20.... these terms..
so form (5,10,15,20,30,35,40,45,55 ) we got 1 no of zero from each.
Now from 25(5*5) and 50(5*5*2) we got 2 no of zeroes form each.
so upto 55 factorial we get (9+4)= 13 zeroes.
so 55! is the smallest value and 59! is the largest value.

Find the no of zeros in the product of 1^1*2^2*3^3*.....*49^49??

consider the case of multiples of 5

5^5 x 10^10 x 15^15 x 20^20 x 25^25 x 30^30 x 35^35 x 40^40 x 45^45
or
5^5 x 10^10 x 15^15 x 20^20 x (5^2)^25 x 30^30 x 35^35 x 40^40 x 45^45
or
5^5 x 10^10 x 15^15 x 20^20 x 5^50 x 30^30 x 35^35 x 40^40 x 45^45

total zeros at the end of product 5^5 x 10^10 x 15^15 x 20^20 x 25^25 x 30^30 x 35^35 x 40^40 x 45^45 will be 5+10+15+20+50+30+35+40+45 = 250 zeros

Ex. 2. How much water must be added to 60 litres of milk at 1 ½ litres for Rs. 2 So as to have a mixture worth Rs.10 2/3 a litre ?

Sol.

C.P. of 1 litre of milk = Rs. (20 x 2/3) = Rs. 40/3c.p of 1 litre of milk c.p of 1 litre of milk 0 Rs.403 Mean price(Rs. 32)3(40/3-32/3)=8/3 (32/3-0)=32/3

∴

Ratio of water and milk =8 : 32 = 8 : 32 = 1 : 433

∴

Quantity of water to be added to 60 litres of milk =

[

1/4 X 60

]

litres =15 litre

A dog taken four leaps for every five leaps of hare but three leaps of the dog is equal to four leaps of the hare. Compare speed?

Let the distance covered in 1 leap of the dog be x and that covered in 1 leap of the hare by y.
Then , 3x = 4y => x =(4/3) y => 4x =(16/3) y

Ratio of speeds of dog and hare = Ratio of distances covered by them in the same time
= 4x : 5y = 16 y : 5y =16 : 5 = 16:15

there are two boxes,one containing 39 red balls & the other containing 26 green balls.you are allowed to move the balls b/w the boxes so that when you choose a box random & a ball at random from the chosen box,the probability of getting a red ball is maximized.this maximum probability is
a)60 b)50 c)80 d)30

Well Keep a single red ball in 1 box and move 38 red balls to the other

1st box = 1R
2nd box = 38R + 26G

p(red) = 1/2 * 1 + 1/2 * 38/64 ≈ 0.8

q.1 in how many ways can 3 postcards can be posted in 5 postboxes?
q.2.in how many ways can 5 postboxes hold 3 post cards?

the correct ans will be 3^5 and 5^3 respectively...

there r three buckets..of 8,5 n 3 litres...out of which only 8 ltr bucket is fully filled...u hv to fill exact 4-4 ltr liquid in 8 and 5 litre bucket by using only these buckets in minimm num of steps......

8ltr 5ltr 3ltr
5 0 3
5 3 0
2 3 3
2 5 1
7 0 1
7 1 0
4 1 3
4 4 0
total 8 steps are required........

8ltr 5ltr 3ltr
initially 8 0 0
step1 3 5 0
step2 3 2 3
step3 6 2 0
step4 6 0 2
step5 1 5 2
step 6 1 4 3
step 7 4 4 0
total 7 steps

The climb from foot to top of a hill 800 meters, Jack can climb at 16 meters per minute and rests for two minutes or 20meters per 2 minutes and rest for one minute. Paul can climb at 10 meters per one minute and rest for one minute or16 meters per minute and rest for 2 minutes. If take has to reach the top in exactly two hours. What is the maximum number of rests that he can take?
a) 41 b) 42 c) 40 d) 43

total=800m
16m per min means for 1m=800/16 =50min to climb
10m per min means for 1m=800/10=80min to climb for paul .....the total time is

2hours==120min....so,time taken for rest by paul is 120-80=40min

Raj tossed 3 dices and there results are noted down then what is the probability that raj gets 10?
a) 1/72 b) 1/9 c) 25/216 d)1/8

Simple solve it 1/8

• Probability of a sum of 3: 1/216 = 0.5%
• Probability of a sum of 4: 3/216 = 1.4%
• Probability of a sum of 5: 6/216 = 2.8%
• Probability of a sum of 6: 10/216 = 4.6%
• Probability of a sum of 7: 15/216 = 7.0%
• Probability of a sum of 8: 21/216 = 9.7%
• Probability of a sum of 9: 25/216 = 11.6%
• Probability of a sum of 10: 27/216 = 12.5%
• Probability of a sum of 11: 27/216 = 12.5%
• Probability of a sum of 12: 25/216 = 11.6%
• Probability of a sum of 13: 21/216 = 9.7%
• Probability of a sum of 14: 15/216 = 7.0%
• Probability of a sum of 15: 10/216 = 4.6%
• Probability of a sum of 16: 6/216 = 2.8%
• Probability of a sum of 17: 3/216 = 1.4%
• Probability of a sum of 18: 1/216 = 0.5%

Apple costs L rupees per kilogram for first 30kgs and Q rupees per kilogram for each additional kilogram. If the price of 33 kilograms is 11.67and for 36kgs of Apples is 12.48 then the cost of first 10 kegs of Apples is
a) 3.50 b) 10.53 c) 1.17 d)2.8

30L+3Q=11.67
30L+6Q=12.48
------------
3Q=.81 Q= .27
from that L=0.362 cost of 10 kg apple is 10*.362=3.6

The letters in the word ABUSER are permuted in all possible ways and arranged in alphabetical order then find the word at position 49 in the permuted alphabetical order?
a) ARBSEU
b) ARBESU
c) ARBSUE
d) ARBEUS

AB**** =4!= 24 ways
AE****=4!=24 ways next word is 49th so
AR**** in alphabetical order **** will be BESU
ans is B

A is twice efficient than B. A and B can both work together to complete a work in 7 days. Then find in how many days A alone can complete the work?

Ans 10.5 try it

In 8*8 chess board what is the total number of squares.

1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2=204....
formula=1^2+2^2+3^2+....+n^2