Showing posts with label TCS 2013 placement new pattern questions 08. Show all posts
Showing posts with label TCS 2013 placement new pattern questions 08. Show all posts

Sunday, October 7, 2012

TCS 2013 placement new pattern questions 08

>> A sequence {An}is defined A(1)=0&A(n+1)=A(n)+2(n)WHAT IS VALUE OF A(100)(a)9902(B)9900(C)10100(D)9904
Last will be A (1) +2*99*98*.....1
Now put the value 1+2(1+2+......+99)
2+ 2*99(99+1)/2
=9902


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